What is ((x^{n+1}+x^{n-1}))/((x^2+1)) ?

The solution to ((x^{n+1}+x^{n-1}))/((x^2+1)) is x^{n-1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((x^{n+1}+x^{n-1}))/((x^2+1))

simplify

\frac{( x ^{n + 1} + x ^{n - 1} )}{( x ^{2} + 1 )}

x^{n - 1}

Solution steps

\frac{x ^{n + 1} + x ^{n - 1}}{x ^{2} + 1}

Factor out common term

x^{n - 1} : x^{n - 1} (x^{2} + 1)

= \frac{x ^{n - 1} ( x ^{2} + 1 )}{x ^{2} + 1}

Cancel the common factor:

x^{2} + 1

= x^{n - 1}

- (a + b) 3 - 8 (a - b)^{3}

7 a - 8 b - 9 a + 2 b

\frac{n !}{( 2 n ! )}

- 3 x - 3 y

\frac{( x - y ) ^{3}}{( y - x ) ^{5}}

What is ((x^{n+1}+x^{n-1}))/((x^2+1)) ?
The solution to ((x^{n+1}+x^{n-1}))/((x^2+1)) is x^{n-1}