What is (((a-b)^2+(b-c)^2+(a-c)^2))/(12) ?

The solution to (((a-b)^2+(b-c)^2+(a-c)^2))/(12) is (a^2-ab+b^2-bc+c^2-ac)/6

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simplify (((a-b)^2+(b-c)^2+(a-c)^2))/(12)

simplify

\frac{( ( a - b ) ^{2} + ( b - c ) ^{2} + ( a - c ) ^{2} )}{12}

\frac{a ^{2} - ab + b ^{2} - b c + c ^{2} - a c}{6}

Solution steps

\frac{( a - b ) ^{2} + ( b - c ) ^{2} + ( a - c ) ^{2}}{12}

Expand

(a - b)^{2} + (b - c)^{2} + (a - c)^{2} : 2 a^{2} - 2 ab + 2 b^{2} - 2 b c + 2 c^{2} - 2 a c

= \frac{2 a ^{2} - 2 ab + 2 b ^{2} - 2 b c + 2 c ^{2} - 2 a c}{12}

Factor out common term

2

= \frac{2 ( a ^{2} - ab + b ^{2} - b c + c ^{2} - a c )}{12}

Factor the number:

12 = 2 \cdot 6

= \frac{2 ( a ^{2} - ab + b ^{2} - b c + c ^{2} - a c )}{2 \cdot 6}

Cancel the common factor:

2

= \frac{a ^{2} - ab + b ^{2} - b c + c ^{2} - a c}{6}

\frac{4 ( x - 6 ) ^{2}}{( x - 6 )}

- 3 (20 + (- 29) d)

(x^{2} - 6 x + 8) (x - 2)

\cdot (g^{4} \cdot h)^{2} \cdot (2 g^{3} \cdot h^{- 1})^{2}

\frac{18}{2} m + \frac{5}{6} m + \frac{6}{m}

What is (((a-b)^2+(b-c)^2+(a-c)^2))/(12) ?
The solution to (((a-b)^2+(b-c)^2+(a-c)^2))/(12) is (a^2-ab+b^2-bc+c^2-ac)/6