What is l^{-1}*{1/s*(sin(1))/s } ?

The solution to l^{-1}*{1/s*(sin(1))/s } is (sin(1))/(ls^2)

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simplify l^{-1}{1/s(sin(1))/s }

simplify

l^{- 1} \cdot {\frac{1}{s} \cdot \frac{sin ( 1 )}{s}}

\frac{sin ( 1 )}{l s ^{2}}

Solution steps

l^{- 1} (\frac{1}{s} \cdot \frac{sin ( 1 )}{s})

Apply exponent rule:

a^{- 1} = \frac{1}{a}

l^{- 1} = \frac{1}{l}

= \frac{1}{l} \cdot \frac{1}{s} \cdot \frac{sin ( 1 )}{s}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1 \cdot sin ( 1 )}{l ss}

1 \cdot 1 \cdot sin (1) = sin (1)

= \frac{sin ( 1 )}{l ss}

Apply exponent rule:

aa = a^{2}

ss = s^{2}

= \frac{sin ( 1 )}{l s ^{2}}

\frac{( 9 x ^{4} - 6 x ^{3} + 11 )}{( - 9 x ^{4} )}

t^{4} - t

\frac{( y ^{2} - 25 )}{( y ^{2} - 10 y + 25 )}

\frac{( x - 2 )}{y} + \frac{( 3 y )}{x}

3 x^{\frac{1}{6}} \cdot 4 x^{\frac{- 7}{6}}

What is l^{-1}*{1/s*(sin(1))/s } ?
The solution to l^{-1}*{1/s*(sin(1))/s } is (sin(1))/(ls^2)