What is ((16*(x+1)^4-x-1))/((x+2)) ?

The solution to ((16*(x+1)^4-x-1))/((x+2)) is (16x^4+64x^3+96x^2+63x+15)/(x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((16*(x+1)^4-x-1))/((x+2))

simplify

\frac{( 16 \cdot ( x + 1 ) ^{4} - x - 1 )}{( x + 2 )}

\frac{16 x ^{4} + 64 x ^{3} + 96 x ^{2} + 63 x + 15}{x + 2}

Solution steps

\frac{16 ( x + 1 ) ^{4} - x - 1}{x + 2}

Expand

16 (x + 1)^{4} - x - 1 : 16 x^{4} + 64 x^{3} + 96 x^{2} + 63 x + 15

= \frac{16 x ^{4} + 64 x ^{3} + 96 x ^{2} + 63 x + 15}{x + 2}

24 a^{3} + 37 a^{2} - 5 a

(2 cos^{2} (x))^{2}

(m + n)^{2} \cdot [(m + n)^{2} - 2 (m^{2} + n^{2})]

- x^{2} - 29 x - 156

o (\frac{n ^{2}}{lo g _{10} ( n )})

What is ((16*(x+1)^4-x-1))/((x+2)) ?
The solution to ((16*(x+1)^4-x-1))/((x+2)) is (16x^4+64x^3+96x^2+63x+15)/(x+2)