What is ((x^3+4x^2-x-4))/((x^2+3x-4)) ?

The solution to ((x^3+4x^2-x-4))/((x^2+3x-4)) is x+1

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simplify ((x^3+4x^2-x-4))/((x^2+3x-4))

simplify

\frac{( x ^{3} + 4 x ^{2} - x - 4 )}{( x ^{2} + 3 x - 4 )}

x + 1

Solution steps

\frac{x ^{3} + 4 x ^{2} - x - 4}{x ^{2} + 3 x - 4}

Factor

x^{3} + 4 x^{2} - x - 4 : (x + 4) (x + 1) (x - 1)

= \frac{( x + 4 ) ( x + 1 ) ( x - 1 )}{x ^{2} + 3 x - 4}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{( x + 4 ) ( x + 1 ) ( x - 1 )}{( x - 1 ) ( x + 4 )}

Cancel the common factor:

x + 4

= \frac{( x + 1 ) ( x - 1 )}{x - 1}

Cancel the common factor:

x - 1

= x + 1

5 a^{2} \cdot b^{2} \cdot c^{2}

5 - (3 x^{2} - 2 x) (6 - 3 x^{2} + 2 x)

- 2 x^{35} f^{5} - 316

a^{3} \cdot x - a^{2} \cdot y

\frac{( 25 x ^{2} - 1 )}{( 25 x ^{2} - 10 x + 1 )}

What is ((x^3+4x^2-x-4))/((x^2+3x-4)) ?
The solution to ((x^3+4x^2-x-4))/((x^2+3x-4)) is x+1