What is (1+(d^2)/5+6 d/5)^{-1} ?

The solution to (1+(d^2)/5+6 d/5)^{-1} is 5/(5+d^2+6d)

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simplify (1+(d^2)/5+6 d/5)^{-1}

simplify

(1 + \frac{d ^{2}}{5} + 6 \frac{d}{5})^{- 1}

\frac{5}{5 + d ^{2} + 6 d}

Solution steps

(1 + \frac{d ^{2}}{5} + 6 \cdot \frac{d}{5})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(1 + \frac{d ^{2}}{5} + 6 \cdot \frac{d}{5})^{- 1} = \frac{1}{1 + \frac{d ^{2}}{5} + 6 \cdot \frac{d}{5}}

= \frac{1}{1 + \frac{d ^{2}}{5} + 6 \cdot \frac{d}{5}}

Simplify

\frac{1}{1 + \frac{d ^{2}}{5} + 6 \cdot \frac{d}{5}} : \frac{5}{5 + d ^{2} + 6 d}

= \frac{5}{5 + d ^{2} + 6 d}

10 (x + 1) - 5 (x - 1.2) + 35

x^{3} + x (x + 12) + 4 x^{2}

11 x^{2} - 88 x - 132

x^{2} \cdot (\frac{x}{y} - \frac{y}{x}) \cdot (\frac{y}{x} + \frac{x}{y}) \cdot y^{2}

(5 \frac{x}{7} + 3 \frac{y}{5})^{3}

What is (1+(d^2)/5+6 d/5)^{-1} ?
The solution to (1+(d^2)/5+6 d/5)^{-1} is 5/(5+d^2+6d)