What is ((6x^3-17x^2+16))/((3x-4)) ?

The solution to ((6x^3-17x^2+16))/((3x-4)) is 2x^2-3x-4

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simplify ((6x^3-17x^2+16))/((3x-4))

simplify

\frac{( 6 x ^{3} - 17 x ^{2} + 16 )}{( 3 x - 4 )}

2 x^{2} - 3 x - 4

Solution steps

\frac{6 x ^{3} - 17 x ^{2} + 16}{3 x - 4}

Factor

6 x^{3} - 17 x^{2} + 16 : (3 x - 4) (2 x^{2} - 3 x - 4)

= \frac{( 3 x - 4 ) ( 2 x ^{2} - 3 x - 4 )}{3 x - 4}

Cancel the common factor:

3 x - 4

= 2 x^{2} - 3 x - 4

(\frac{2}{3 x + 1})^{- 1}

\frac{7 x ^{4} + x ^{5} - 2 x ^{2} - 9 x ^{3} + x ^{2} - 1}{4 x}

x + \frac{2}{x} + 5 + (- 5) x - \frac{1}{x ^{2}} + 6 x + 5 - \frac{1}{1} + x

(3 y + 1)^{3}

(5 x^{9} - 7 x^{\frac{5}{2}} - 7)^{\frac{9}{3}}

What is ((6x^3-17x^2+16))/((3x-4)) ?
The solution to ((6x^3-17x^2+16))/((3x-4)) is 2x^2-3x-4