What is 1/(sec^2(x))+sin^2(x) ?

The solution to 1/(sec^2(x))+sin^2(x) is 1

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simplify 1/(sec^2(x))+sin^2(x)

simplify

\frac{1}{sec ^{2} ( x )} + sin^{2} (x)

1

Solution steps

\frac{1}{sec ^{2} ( x )} + sin^{2} (x)

Rewrite using trig identities

= 1

(+ 5 x^{2})^{2}

(27 x^{- 3} y)^{\frac{1}{3}}

1 + (2 g - h)^{3}

cos^{a + b} (- sin^{2} (a - b))

(- a^{3} b^{2})^{5}