What is (((8x^3*y^2*z))/((12y^3*z^2*x)))^3 ?

The solution to (((8x^3*y^2*z))/((12y^3*z^2*x)))^3 is (8x^6)/(27y^3z^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (((8x^3y^2z))/((12y^3z^2x)))^3

simplify

(\frac{( 8 x ^{3} \cdot y ^{2} \cdot z )}{( 12 y ^{3} \cdot z ^{2} \cdot x )})^{3}

\frac{8 x ^{6}}{27 y ^{3} z ^{3}}

Solution steps

(\frac{8 x ^{3} y ^{2} z}{12 y ^{3} z ^{2} x})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 8 x ^{3} y ^{2} z ) ^{3}}{( 12 y ^{3} z ^{2} x ) ^{3}}

Simplify

(8 x^{3} y^{2} z)^{3} : 512 x^{9} y^{6} z^{3}

= \frac{512 x ^{9} y ^{6} z ^{3}}{( 12 y ^{3} z ^{2} x ) ^{3}}

Simplify

(12 y^{3} z^{2} x)^{3} : 1728 y^{9} z^{6} x^{3}

= \frac{512 x ^{9} y ^{6} z ^{3}}{1728 y ^{9} z ^{6} x ^{3}}

Cancel the common factor:

64

= \frac{8 x ^{9} y ^{6} z ^{3}}{27 x ^{3} y ^{9} z ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{x ^{9}}{x ^{3}} = x^{9 - 3}

= \frac{8 y ^{6} z ^{3} x ^{9 - 3}}{27 y ^{9} z ^{6}}

Subtract the numbers:

9 - 3 = 6

= \frac{8 x ^{6} y ^{6} z ^{3}}{27 y ^{9} z ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{y ^{6}}{y ^{9}} = \frac{1}{y ^{9 - 6}}

= \frac{8 x ^{6} z ^{3}}{27 z ^{6} y ^{9 - 6}}

Subtract the numbers:

9 - 6 = 3

= \frac{8 x ^{6} z ^{3}}{27 y ^{3} z ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{z ^{3}}{z ^{6}} = \frac{1}{z ^{6 - 3}}

= \frac{8 x ^{6}}{27 y ^{3} z ^{6 - 3}}

Subtract the numbers:

6 - 3 = 3

= \frac{8 x ^{6}}{27 y ^{3} z ^{3}}

5 x^{2} + 33 x y - 14 y^{2}

(1 + a^{2})^{- 2}

- x^{2} - x - 2

(x^{x})^{2 x}

(e + r) i^{2}

What is (((8x^3*y^2*z))/((12y^3*z^2*x)))^3 ?
The solution to (((8x^3*y^2*z))/((12y^3*z^2*x)))^3 is (8x^6)/(27y^3z^3)