What is factor a^6-2a^3*b^3+b^6 ?

The solution to factor a^6-2a^3*b^3+b^6 is (a-b)^2(a^2+ab+b^2)^2

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factor a^6-2a^3*b^3+b^6

factor

a^{6} - 2 a^{3} \cdot b^{3} + b^{6}

(a - b)^{2} (a^{2} + ab + b^{2})^{2}

Solution steps

a^{6} - 2 a^{3} b^{3} + b^{6}

Break the expression into groups

= (a^{6} - a^{3} b^{3}) + (- a^{3} b^{3} + b^{6})

Factor out

a^{3}

from

a^{6} - a^{3} b^{3} : a^{3} (a^{3} - b^{3})

Factor out

- b^{3}

from

- a^{3} b^{3} + b^{6} : - b^{3} (a^{3} - b^{3})

= a^{3} (a^{3} - b^{3}) - b^{3} (a^{3} - b^{3})

Factor out common term

a^{3} - b^{3}

= (a^{3} - b^{3}) (a^{3} - b^{3})

Factor

a^{3} - b^{3} : (a - b) (a^{2} + ab + b^{2})

= (a - b) (a^{2} + ab + b^{2}) (a^{3} - b^{3})

Factor

a^{3} - b^{3} : (a - b) (a^{2} + ab + b^{2})

= (a - b) (a^{2} + ab + b^{2}) (a - b) (a^{2} + ab + b^{2})

Simplify

= (a - b)^{2} (a^{2} + ab + b^{2})^{2}

\frac{( 4 x + 8 )}{2}

(x + y)^{3} - (x - y)^{3} - 6 y (x^{2} - y^{2})

\frac{( ( y - 2 ) ( y - 3 ) )}{- 4} \cdot \frac{( - 4 y )}{( y - 2 )}

\frac{- 1}{a ^{b}}

\frac{( 5 - 80 x ^{2} )}{10}

What is factor a^6-2a^3*b^3+b^6 ?
The solution to factor a^6-2a^3*b^3+b^6 is (a-b)^2(a^2+ab+b^2)^2