What is l^+[ s/((s^2+s-2))] ?

The solution to l^+[ s/((s^2+s-2))] is (l^{}s)/(s^2+s-2)

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simplify l^+[ s/((s^2+s-2))]

simplify

l^{+} [\frac{s}{( s ^{2} + s - 2 )}]

\frac{l s}{s ^{2} + s - 2}

Solution steps

l^{+} (\frac{s}{s ^{2} + s - 2})

Remove parentheses:

(a) = a

= l \frac{s}{s ^{2} + s - 2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{l s}{s ^{2} + s - 2}

^{'} arcsin \frac{( 1 )}{( 1 x ^{2} )}^{'}

f (x) + f (5)

8.8 (a + b) \frac{2}{c} - 0 \cdot 5 + \frac{29}{( 9 + y )} (a + b) \cdot (\frac{1}{h})

7 (x + 2) \cdot (x - 7)^{3}

8 x^{6} y^{5} - 3 x^{8} y^{3}

What is l^+[ s/((s^2+s-2))] ?
The solution to l^+[ s/((s^2+s-2))] is (l^{}s)/(s^2+s-2)