What is ((-3x^2+1)/(3y^3))^2 ?

The solution to ((-3x^2+1)/(3y^3))^2 is ((-3x^2+1)^2)/(9y^6)

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simplify ((-3x^2+1)/(3y^3))^2

simplify

(\frac{- 3 x ^{2} + 1}{3 y ^{3}})^{2}

\frac{( - 3 x ^{2} + 1 ) ^{2}}{9 y ^{6}}

Solution steps

(\frac{- 3 x ^{2} + 1}{3 y ^{3}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( - 3 x ^{2} + 1 ) ^{2}}{( 3 y ^{3} ) ^{2}}

Simplify

(3 y^{3})^{2} : 9 y^{6}

= \frac{( - 3 x ^{2} + 1 ) ^{2}}{9 y ^{6}}

(x^{2} - 3 x) - 8 (x^{2} - 3 x) - 20

6.75 x 1 0^{6} \cdot 0.2 x 1 0^{6}

(3 x + 2 y^{2})^{5}

(\cdot 4 y - 3) - 2 (z - 2 \cdot (- 3) y^{2})

108 x^{7} \cdot y^{4} - 4000 x^{4} \cdot y^{7}

What is ((-3x^2+1)/(3y^3))^2 ?
The solution to ((-3x^2+1)/(3y^3))^2 is ((-3x^2+1)^2)/(9y^6)