What is (((16w^8)}{(y^{20})})^{\frac{-3)/4} ?

The solution to (((16w^8)}{(y^{20})})^{\frac{-3)/4} is (y^{15})/(8w^6)

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simplify (((16w^8)}{(y^{20})})^{\frac{-3)/4}

simplify

(\frac{( 16 w ^{8} )}{( y ^{20} )})^{\frac{- 3}{4}}

\frac{y ^{15}}{8 w ^{6}}

Solution steps

(\frac{16 w ^{8}}{y ^{20}})^{\frac{- 3}{4}}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 16 w ^{8} ) ^{\frac{- 3}{4}}}{( y ^{20} ) ^{\frac{- 3}{4}}}

Simplify

(16 w^{8})^{\frac{- 3}{4}} : \frac{1}{8 w ^{6}}

= \frac{\frac{1}{8 w ^{6}}}{( y ^{20} ) ^{\frac{- 3}{4}}}

Simplify

(y^{20})^{\frac{- 3}{4}} : \frac{1}{y ^{15}}

= \frac{\frac{1}{8 w ^{6}}}{\frac{1}{y ^{15}}}

Simplify

\frac{\frac{1}{8 w ^{6}}}{\frac{1}{y ^{15}}} : \frac{y ^{15}}{8 w ^{6}}

= \frac{y ^{15}}{8 w ^{6}}

\frac{( 1 + \frac{a}{b} )}{( 1 + \frac{b}{a} )}

(\frac{9}{16} \frac{x ^{4}}{12}) + (\frac{9}{16} x - \frac{3}{9})

x^{'} - y (\frac{x}{y}) + a (y)^{2}

(2 x^{2} - 3 x + 2 x^{4} - 5) \cdot (- 5 x - x^{2} - 4 + 3 x^{4})

(- 9 w^{3} u)^{2}

What is (((16w^8)}{(y^{20})})^{\frac{-3)/4} ?
The solution to (((16w^8)}{(y^{20})})^{\frac{-3)/4} is (y^{15})/(8w^6)