What is (3b^{-2})^2*(a^2*b^4)^3 ?

The solution to (3b^{-2})^2*(a^2*b^4)^3 is 9a^6b^8

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simplify (3b^{-2})^2(a^2b^4)^3

simplify

(3 b^{- 2})^{2} \cdot (a^{2} \cdot b^{4})^{3}

9 a^{6} b^{8}

Solution steps

(3 b^{- 2})^{2} (a^{2} b^{4})^{3}

Simplify

(3 b^{- 2})^{2} : \frac{9}{b ^{4}}

= \frac{9}{b ^{4}} (a^{2} b^{4})^{3}

Simplify

(a^{2} b^{4})^{3} : a^{6} b^{12}

= \frac{9}{b ^{4}} a^{6} b^{12}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{9 a ^{6} b ^{12}}{b ^{4}}

Simplify

\frac{b ^{12}}{b ^{4}} : b^{8}

= 9 a^{6} b^{8}

\frac{( d ^{3} \cdot x )}{( d \cdot y ^{3} )}

lo g_{10} (b) (\frac{1}{b})

\frac{- ( 12 x ^{6} y ^{2} z ) ^{2}}{( - 6 x ^{2} y ^{2} )}

64 a^{3}

m^{5} + n^{5}

What is (3b^{-2})^2*(a^2*b^4)^3 ?
The solution to (3b^{-2})^2*(a^2*b^4)^3 is 9a^6b^8