What is factor 2x^6-19x^3+24 ?

The solution to factor 2x^6-19x^3+24 is (x-2)(x^2+2x+4)(2x^3-3)

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factor 2x^6-19x^3+24

factor

2 x^{6} - 19 x^{3} + 24

(x - 2) (x^{2} + 2 x + 4) (2 x^{3} - 3)

Solution steps

2 x^{6} - 19 x^{3} + 24

Use the rational root theorem

= (x - 2) \frac{2 x ^{6} - 19 x ^{3} + 24}{x - 2}

\frac{2 x ^{6} - 19 x ^{3} + 24}{x - 2} = 2 x^{5} + 4 x^{4} + 8 x^{3} - 3 x^{2} - 6 x - 12

= (x - 2) (2 x^{5} + 4 x^{4} + 8 x^{3} - 3 x^{2} - 6 x - 12)

Factor

2 x^{5} + 4 x^{4} + 8 x^{3} - 3 x^{2} - 6 x - 12 : (x^{2} + 2 x + 4) (2 x^{3} - 3)

= (x - 2) (x^{2} + 2 x + 4) (2 x^{3} - 3)

tan^{2} (x^{2}) - sin^{2} (2 x)

(\frac{2}{3} \cdot m + \frac{3}{2} \cdot n)^{2}

15 x^{2} - 12 y^{2}

100 x^{2} - (x^{2} + 25)^{2}

(\frac{4 x}{5 - 2})^{3}

What is factor 2x^6-19x^3+24 ?
The solution to factor 2x^6-19x^3+24 is (x-2)(x^2+2x+4)(2x^3-3)