What are the solutions to the equation 2x^2-200=0 ?

The solutions to the equation 2x^2-200=0 are x=10,x=-10

Find the zeros of 2x^2-200=0

The zeros of 2x^2-200=0 are x=10,x=-10

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2 x^{2} - 200 = 0

x = 10, x = - 10

Solution steps

2 x^{2} - 200 = 0

Move

200

to the right side

2 x^{2} = 200

Divide both sides by

2

x^{2} = 100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 100, x = - 100

100 = 10

- 100 = - 10

x = 10, x = - 10

2 w \geq - 10

3 x - 3

\frac{13 !}{( 13 - 5 ) ! 5 !}

\frac{x + 2}{6} = \frac{2 x - 10}{8} 5360

8 z + 7 < 3 z - 4

What are the solutions to the equation 2x^2-200=0 ?
The solutions to the equation 2x^2-200=0 are x=10,x=-10
Find the zeros of 2x^2-200=0
The zeros of 2x^2-200=0 are x=10,x=-10