What is ((x^3+2x^2-x-2))/((x^3+4x^2+x-6)) ?

The solution to ((x^3+2x^2-x-2))/((x^3+4x^2+x-6)) is (x+1)/(x+3)

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simplify ((x^3+2x^2-x-2))/((x^3+4x^2+x-6))

simplify

\frac{( x ^{3} + 2 x ^{2} - x - 2 )}{( x ^{3} + 4 x ^{2} + x - 6 )}

\frac{x + 1}{x + 3}

Solution steps

\frac{x ^{3} + 2 x ^{2} - x - 2}{x ^{3} + 4 x ^{2} + x - 6}

Factor

x^{3} + 2 x^{2} - x - 2 : (x + 2) (x + 1) (x - 1)

= \frac{( x + 2 ) ( x + 1 ) ( x - 1 )}{x ^{3} + 4 x ^{2} + x - 6}

Factor

x^{3} + 4 x^{2} + x - 6 : (x - 1) (x + 2) (x + 3)

= \frac{( x + 2 ) ( x + 1 ) ( x - 1 )}{( x - 1 ) ( x + 2 ) ( x + 3 )}

Cancel the common factor:

x + 2

= \frac{( x + 1 ) ( x - 1 )}{( x - 1 ) ( x + 3 )}

Cancel the common factor:

x - 1

= \frac{x + 1}{x + 3}

169 x^{6} \cdot y^{4} + 26 x^{2} \cdot y^{3} \cdot z

(1 - x^{4})^{7}

8 x^{6} + 125

\frac{l ^{- 1} \cdot s}{( ( s ^{2} + 1 ) ( s ^{2} + 4 ) ( s ^{2} + 9 ) )}

- 1 x y + 5 x y^{2} z

What is ((x^3+2x^2-x-2))/((x^3+4x^2+x-6)) ?
The solution to ((x^3+2x^2-x-2))/((x^3+4x^2+x-6)) is (x+1)/(x+3)