What is sin(x-1)(x+1)^{-1} ?

The solution to sin(x-1)(x+1)^{-1} is (sin(x-1))/(x+1)

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simplify sin(x-1)(x+1)^{-1}

simplify

sin (x - 1) (x + 1)^{- 1}

\frac{sin ( x - 1 )}{x + 1}

Solution steps

sin (x - 1) (x + 1)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(x + 1)^{- 1} = \frac{1}{x + 1}

= sin (x - 1) \frac{1}{x + 1}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( x - 1 ) \cdot 1}{x + 1}

Apply rule:

a \cdot 1 = a

sin (x - 1) \cdot 1 = sin (x - 1)

= \frac{sin ( x - 1 )}{x + 1}

6 x^{2} - 54 y^{2}

x + 224 \cdot 3

sin^{2} (\frac{x}{2}) + cos^{2} (\frac{x}{2})

(60 - x)^{3}

14 \cdot (3 y - 5 z)^{3} + 7 \cdot (3 y - 5 z)^{2}

What is sin(x-1)(x+1)^{-1} ?
The solution to sin(x-1)(x+1)^{-1} is (sin(x-1))/(x+1)