What is ((x^4-16))/((x^3-8)) ?

The solution to ((x^4-16))/((x^3-8)) is ((x^2+4)(x+2))/(x^2+2x+4)

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simplify ((x^4-16))/((x^3-8))

simplify

\frac{( x ^{4} - 16 )}{( x ^{3} - 8 )}

\frac{( x ^{2} + 4 ) ( x + 2 )}{x ^{2} + 2 x + 4}

Solution steps

\frac{x ^{4} - 16}{x ^{3} - 8}

Factor

x^{4} - 16 : (x^{2} + 4) (x + 2) (x - 2)

= \frac{( x ^{2} + 4 ) ( x + 2 ) ( x - 2 )}{x ^{3} - 8}

Factor

x^{3} - 8 : (x - 2) (x^{2} + 2 x + 4)

= \frac{( x ^{2} + 4 ) ( x + 2 ) ( x - 2 )}{( x - 2 ) ( x ^{2} + 2 x + 4 )}

Cancel the common factor:

x - 2

= \frac{( x ^{2} + 4 ) ( x + 2 )}{x ^{2} + 2 x + 4}

(16 z)^{- 3} \cdot (4 z)^{3}

6 x - 3 y + 9

(x + 3) (x - 3) + 81

30 (x^{3}) - 31 (x^{2}) + 10 x - 1

(- 6 m^{- 1} \cdot n^{0})^{- 2}

What is ((x^4-16))/((x^3-8)) ?
The solution to ((x^4-16))/((x^3-8)) is ((x^2+4)(x+2))/(x^2+2x+4)