What is (y^{1/3})/(((y^{-1/2))(y^{1/4}))} ?

The solution to (y^{1/3})/(((y^{-1/2))(y^{1/4}))} is y^{7/12}

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simplify (y^{1/3})/(((y^{-1/2))(y^{1/4}))}

simplify

\frac{y ^{\frac{1}{3}}}{( ( y ^{- \frac{1}{2}} ) ( y ^{\frac{1}{4}} ) )}

y^{\frac{7}{12}}

Solution steps

\frac{y ^{\frac{1}{3}}}{( y ^{- \frac{1}{2}} ) ( y ^{\frac{1}{4}} )}

Simplify

(y^{- \frac{1}{2}}) (y^{\frac{1}{4}}) : y^{- \frac{1}{2}} y^{\frac{1}{4}}

= \frac{y ^{\frac{1}{3}}}{y ^{- \frac{1}{2}} y ^{\frac{1}{4}}}

Simplify

\frac{y ^{\frac{1}{3}}}{y ^{- \frac{1}{2}}} : y^{\frac{5}{6}}

= \frac{y ^{\frac{5}{6}}}{y ^{\frac{1}{4}}}

Simplify

\frac{y ^{\frac{5}{6}}}{y ^{\frac{1}{4}}} : y^{\frac{7}{12}}

= y^{\frac{7}{12}}

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What is (y^{1/3})/(((y^{-1/2))(y^{1/4}))} ?
The solution to (y^{1/3})/(((y^{-1/2))(y^{1/4}))} is y^{7/12}