What is 1/z+4/(z^2)+8/(z^3) ?

The solution to 1/z+4/(z^2)+8/(z^3) is (z^2+4z+8)/(z^3)

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simplify 1/z+4/(z^2)+8/(z^3)

simplify

\frac{1}{z} + \frac{4}{z ^{2}} + \frac{8}{z ^{3}}

\frac{z ^{2} + 4 z + 8}{z ^{3}}

Solution steps

\frac{1}{z} + \frac{4}{z ^{2}} + \frac{8}{z ^{3}}

Least Common Multiplier of

z, z^{2}, z^{3} : z^{3}

Adjust Fractions based on the LCM

= \frac{z ^{2}}{z ^{3}} + \frac{4 z}{z ^{3}} + \frac{8}{z ^{3}}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{z ^{2} + 4 z + 8}{z ^{3}}

\frac{( 7 m - 70 n ^{3} )}{7}

\frac{lo g _{10} ( x ^{1} )}{x}

32 x^{2} \cdot y - 48 x^{3} \cdot y^{3}

\frac{a ^{2} - a - 90}{100 - a ^{2}}

(\frac{6 x - 1}{2 y})^{2}

What is 1/z+4/(z^2)+8/(z^3) ?
The solution to 1/z+4/(z^2)+8/(z^3) is (z^2+4z+8)/(z^3)