What is ((m^3-m^4))/((m^2-8m+7)) ?

The solution to ((m^3-m^4))/((m^2-8m+7)) is -(m^3)/(m-7)

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simplify ((m^3-m^4))/((m^2-8m+7))

simplify

\frac{( m ^{3} - m ^{4} )}{( m ^{2} - 8 m + 7 )}

- \frac{m ^{3}}{m - 7}

Solution steps

\frac{m ^{3} - m ^{4}}{m ^{2} - 8 m + 7}

Factor

m^{3} - m^{4} : m^{3} (1 - m)

= \frac{m ^{3} ( 1 - m )}{m ^{2} - 8 m + 7}

Factor

m^{2} - 8 m + 7 : (m - 1) (m - 7)

= \frac{m ^{3} ( 1 - m )}{( m - 1 ) ( m - 7 )}

m^{3} (1 - m) = - m^{3} (m - 1)

= \frac{- m ^{3} ( m - 1 )}{( m - 1 ) ( m - 7 )}

Cancel the common factor:

m - 1

= \frac{- m ^{3}}{m - 7}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{m ^{3}}{m - 7}

x^{4} y^{3} + x^{5} y^{5}

x^{3} + 3 x + 3 x^{2} + 1

\frac{( 4 ( y + 1 ) )}{( ( y + 1 ) ( y - 1 ) )}

\frac{20 x ^{7} - 3 x ^{6} + 12 x ^{5} - 24 x ^{4}}{- 4 x ^{4}}

27 a^{3} - 64

What is ((m^3-m^4))/((m^2-8m+7)) ?
The solution to ((m^3-m^4))/((m^2-8m+7)) is -(m^3)/(m-7)