What are the solutions to the equation X^2+7X+12=0 ?

The solutions to the equation X^2+7X+12=0 are X=-3,X=-4

Find the zeros of X^2+7X+12=0

The zeros of X^2+7X+12=0 are X=-3,X=-4

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X^{2} + 7 X + 12 = 0

X = - 3, X = - 4

Solution steps

X^{2} + 7 X + 12 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

X_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 7 + 1}{2 \cdot 1}, X_{2} = \frac{- 7 - 1}{2 \cdot 1}

X = \frac{- 7 + 1}{2 \cdot 1} : - 3

X = \frac{- 7 - 1}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

X = - 3, X = - 4

2 x^{2} + 2 x + 6

x + 2 \geq x - 3

1 - 0.4 x - 0.3 x^{2} = 0

a^{2} + 2 a + 10 = 0

x^{3} + 4 x^{2} + 6 x + 24

What are the solutions to the equation X^2+7X+12=0 ?
The solutions to the equation X^2+7X+12=0 are X=-3,X=-4
Find the zeros of X^2+7X+12=0
The zeros of X^2+7X+12=0 are X=-3,X=-4