What is factor (x^3-3x^2-4x)^{0.5} ?

The solution to factor (x^3-3x^2-4x)^{0.5} is x^{0.5}(x+1)^{0.5}(x-4)^{0.5}

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factor (x^3-3x^2-4x)^{0.5}

factor

(x^{3} - 3 x^{2} - 4 x)^{0.5}

x^{0.5} (x + 1)^{0.5} (x - 4)^{0.5}

Solution steps

(x^{3} - 3 x^{2} - 4 x)^{0.5}

Factor

x^{3} - 3 x^{2} - 4 x : x (x + 1) (x - 4)

= (x (x + 1) (x - 4))^{0.5}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(x (x + 1) (x - 4))^{0.5} = x^{0.5} (x + 1)^{0.5} (x - 4)^{0.5}

= x^{0.5} (x + 1)^{0.5} (x - 4)^{0.5}

(\frac{a}{3} - \frac{b}{5}) (\frac{3}{a} - \frac{5}{b})

- 3 x^{2} - 16 x - 75

(2 a^{2} - b)^{3}

(1 - x)^{- 2} - (1 - x)^{\frac{1}{2}}

2 x + x (x - 2) 6 + x (x - 2) (x - 4)

What is factor (x^3-3x^2-4x)^{0.5} ?
The solution to factor (x^3-3x^2-4x)^{0.5} is x^{0.5}(x+1)^{0.5}(x-4)^{0.5}