What is ((x^2+4x+4))/((sqrt(2)+1)) ?

The solution to ((x^2+4x+4))/((sqrt(2)+1)) is (sqrt(2)-1)(x^2+4x+4)

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simplify ((x^2+4x+4))/((sqrt(2)+1))

simplify

\frac{( x ^{2} + 4 x + 4 )}{( 2 + 1 )}

(2 - 1) (x^{2} + 4 x + 4)

Solution steps

\frac{x ^{2} + 4 x + 4}{2 + 1}

Multiply by the conjugate

\frac{2 - 1}{2 - 1}

= \frac{( x ^{2} + 4 x + 4 ) ( 2 - 1 )}{( 2 + 1 ) ( 2 - 1 )}

(2 + 1) (2 - 1) = 1

= \frac{( 2 - 1 ) ( x ^{2} + 4 x + 4 )}{1}

Apply rule

\frac{a}{1} = a

= (2 - 1) (x^{2} + 4 x + 4)

5 20 z + 45 z

2 ∣ a + b ∣ + 3 ∣ a - b ∣ - ∣ b ∣^{2}

(3 x - 5) (2 x + 2)

(8 x^{- 5})^{- 3}

p (x) + 2 q (x)

What is ((x^2+4x+4))/((sqrt(2)+1)) ?
The solution to ((x^2+4x+4))/((sqrt(2)+1)) is (sqrt(2)-1)(x^2+4x+4)