What is (3/(x+4x))((-2x-7)/x) ?

The solution to (3/(x+4x))((-2x-7)/x) is (3(-2x-7))/(5x^2)

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simplify (3/(x+4x))((-2x-7)/x)

simplify

(\frac{3}{x + 4 x}) (\frac{- 2 x - 7}{x})

\frac{3 ( - 2 x - 7 )}{5 x ^{2}}

Solution steps

(\frac{3}{x + 4 x}) (\frac{- 2 x - 7}{x})

Simplify

(\frac{3}{x + 4 x}) (\frac{- 2 x - 7}{x}) : \frac{3}{x + 4 x} \cdot \frac{- 2 x - 7}{x}

= \frac{3}{x + 4 x} \cdot \frac{- 2 x - 7}{x}

Add similar elements:

x + 4 x = 5 x

= \frac{3}{5 x} \cdot \frac{- 2 x - 7}{x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 ( - 2 x - 7 )}{5 xx}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{3 ( - 2 x - 7 )}{5 x ^{2}}

3 x^{2.5} \cdot 3 x^{2.5} \cdot 3 x^{2.5} \cdot 3 x^{2.5}

l^{- 1} [\frac{10}{( s + 6 ) ^{6}}]

5 (- a^{3} b^{2} c)^{3}

- 512 (x^{1})^{7} + 64 x^{8}

\frac{( 1.2 x 1 0 ^{4} )}{( 6 x 1 0 ^{- 2} )}

What is (3/(x+4x))((-2x-7)/x) ?
The solution to (3/(x+4x))((-2x-7)/x) is (3(-2x-7))/(5x^2)