What is 2m^4-m^2x^2-8 x/(x^2)-x-m ?

The solution to 2m^4-m^2x^2-8 x/(x^2)-x-m is 2m^4-m^2x^2-8/x-x-m

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simplify 2m^4-m^2x^2-8 x/(x^2)-x-m

simplify

2 m^{4} - m^{2} x^{2} - 8 \frac{x}{x ^{2}} - x - m

2 m^{4} - m^{2} x^{2} - \frac{8}{x} - x - m

Solution steps

2 m^{4} - m^{2} x^{2} - 8 \cdot \frac{x}{x ^{2}} - x - m

Cancel

\frac{x}{x ^{2}} : \frac{1}{x}

= 2 m^{4} - m^{2} x^{2} - 8 \cdot \frac{1}{x} - x - m

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

8 \cdot \frac{1}{x} = \frac{8 \cdot 1}{x}

= 2 m^{4} - m^{2} x^{2} - \frac{8 \cdot 1}{x} - x - m

Multiply the numbers:

8 \cdot 1 = 8

= 2 m^{4} - m^{2} x^{2} - \frac{8}{x} - x - m

tan^{3} (\frac{x}{sin ( x )})

9 \frac{x}{( x - 2 )} + \frac{2}{x}

(5 a + 6)^{3}

55506 - 0 k^{30}

x^{6} - 4 x^{3} \cdot y + 4 x

What is 2m^4-m^2x^2-8 x/(x^2)-x-m ?
The solution to 2m^4-m^2x^2-8 x/(x^2)-x-m is 2m^4-m^2x^2-8/x-x-m