What are the solutions to the equation -x^2+1=0 ?

The solutions to the equation -x^2+1=0 are x=1,x=-1

Find the zeros of -x^2+1=0

The zeros of -x^2+1=0 are x=1,x=-1

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- x^{2} + 1 = 0

x = 1, x = - 1

Solution steps

- x^{2} + 1 = 0

Move

1

to the right side

- x^{2} = - 1

Divide both sides by

- 1

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

- [2 x - (5 x + 2)] = 2 + (2 x + 7)

x^{2} = - 676

2 x^{2} - 8

\frac{6 ( x + 2 )}{2} = \frac{12 x}{4} + 6

(x + 2)^{2} = - 3 (22 + 5 x)

What are the solutions to the equation -x^2+1=0 ?
The solutions to the equation -x^2+1=0 are x=1,x=-1
Find the zeros of -x^2+1=0
The zeros of -x^2+1=0 are x=1,x=-1