What is ([sin(a/2)sin(c/2)])/(sin(b/2)) ?

The solution to ([sin(a/2)sin(c/2)])/(sin(b/2)) is sin(a/2)sin(c/2)csc(b/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ([sin(a/2)sin(c/2)])/(sin(b/2))

simplify

\frac{[ sin ( \frac{a}{2} ) sin ( \frac{c}{2} ) ]}{sin ( \frac{b}{2} )}

sin (\frac{a}{2}) sin (\frac{c}{2}) csc (\frac{b}{2})

Solution steps

\frac{sin ( \frac{a}{2} ) sin ( \frac{c}{2} )}{sin ( \frac{b}{2} )}

Use the basic trigonometric identity:

\frac{1}{sin ( x )} = csc (x)

= sin (\frac{a}{2}) sin (\frac{c}{2}) csc (\frac{b}{2})

5 + 5 - (2 x^{0}) + 4 - 1

(0) (y - 3) (x - 2 y - 3 z)

(x - y)^{\frac{- 1}{2}}

f (x) = 3.2 x^{10} - 4

4 x^{2} y - 4 y^{3}

What is ([sin(a/2)sin(c/2)])/(sin(b/2)) ?
The solution to ([sin(a/2)sin(c/2)])/(sin(b/2)) is sin(a/2)sin(c/2)csc(b/2)