What is 1/((3d^2-4)*(cos^3(x))) ?

The solution to 1/((3d^2-4)*(cos^3(x))) is (sec^3(x))/(3d^2-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 1/((3d^2-4)*(cos^3(x)))

simplify

\frac{1}{( 3 d ^{2} - 4 ) \cdot ( cos ^{3} ( x ) )}

\frac{sec ^{3} ( x )}{3 d ^{2} - 4}

Solution steps

\frac{1}{( 3 d ^{2} - 4 ) ( cos ^{3} ( x ) )}

Use the basic trigonometric identity:

\frac{1}{cos ( x )} = sec (x)

= \frac{sec ^{3} ( x )}{3 d ^{2} - 4}

\frac{4 \times ( \frac{100}{10} )}{28 + 15}

\frac{y ^{3}}{y ^{- 2}}

4 x^{2} - 8 x y^{2} + 10 x^{2} y^{2}

∣ x + y ∣^{2} + ∣ x - y ∣^{2}

f^{'} (x) \frac{( x )}{f ( x ) ( x ) ^{2}} (x)

What is 1/((3d^2-4)*(cos^3(x))) ?
The solution to 1/((3d^2-4)*(cos^3(x))) is (sec^3(x))/(3d^2-4)