What are the solutions to the equation K^2+9K+20=0 ?

The solutions to the equation K^2+9K+20=0 are K=-4,K=-5

Find the zeros of K^2+9K+20=0

The zeros of K^2+9K+20=0 are K=-4,K=-5

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K^{2} + 9 K + 20 = 0

K = - 4, K = - 5

Solution steps

K^{2} + 9 K + 20 = 0

Solve with the quadratic formula

K_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

K_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

K_{1} = \frac{- 9 + 1}{2 \cdot 1}, K_{2} = \frac{- 9 - 1}{2 \cdot 1}

K = \frac{- 9 + 1}{2 \cdot 1} : - 4

K = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

K = - 4, K = - 5

x^{2} + 7 x + 15 = 5

\frac{4}{52} + \frac{4}{52}

- 4 x - 4 = 0

∣ s + 4 ∣ > 2

x^{2} - 7 x + 10

What are the solutions to the equation K^2+9K+20=0 ?
The solutions to the equation K^2+9K+20=0 are K=-4,K=-5
Find the zeros of K^2+9K+20=0
The zeros of K^2+9K+20=0 are K=-4,K=-5