What is ((x^2-1))/((x+1))*((x^2+x))/((x^2-x)) ?

The solution to ((x^2-1))/((x+1))*((x^2+x))/((x^2-x)) is x+1

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simplify ((x^2-1))/((x+1))*((x^2+x))/((x^2-x))

simplify

\frac{( x ^{2} - 1 )}{( x + 1 )} \cdot \frac{( x ^{2} + x )}{( x ^{2} - x )}

x + 1

Solution steps

\frac{x ^{2} - 1}{x + 1} \cdot \frac{x ^{2} + x}{x ^{2} - x}

Cancel

\frac{x ^{2} - 1}{x + 1} : x - 1

= (x - 1) \frac{x ^{2} + x}{x ^{2} - x}

Cancel

\frac{x ^{2} + x}{x ^{2} - x} : \frac{x + 1}{x - 1}

= (x - 1) \frac{x + 1}{x - 1}

Cross-cancel common factor:

x - 1

= x + 1

c {(2^{0} + 3^{- 1}) \cdot 9^{2}}

6.023 x 1 0^{23} + 8976.72 x 1 0^{19}

(8 t)^{4}

\frac{x ^{2}}{( x - y )} + \frac{y ^{2}}{( y - x )}

\frac{( 4 x ^{3} - 3 x ^{2} - 11 x + 7 )}{( x ^{2} + x - 1 )}

What is ((x^2-1))/((x+1))*((x^2+x))/((x^2-x)) ?
The solution to ((x^2-1))/((x+1))*((x^2+x))/((x^2-x)) is x+1