What is ((x^5y)/(2x^3y^4))^3 ?

The solution to ((x^5y)/(2x^3y^4))^3 is (x^6)/(8y^9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((x^5y)/(2x^3y^4))^3

simplify

(\frac{x ^{5} y}{2 x ^{3} y ^{4}})^{3}

\frac{x ^{6}}{8 y ^{9}}

Solution steps

(\frac{x ^{5} y}{2 x ^{3} y ^{4}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( x ^{5} y ) ^{3}}{( 2 x ^{3} y ^{4} ) ^{3}}

Simplify

(x^{5} y)^{3} : x^{15} y^{3}

= \frac{x ^{15} y ^{3}}{( 2 x ^{3} y ^{4} ) ^{3}}

Simplify

(2 x^{3} y^{4})^{3} : 8 x^{9} y^{12}

= \frac{x ^{15} y ^{3}}{8 x ^{9} y ^{12}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{x ^{15}}{x ^{9}} = x^{15 - 9}

= \frac{y ^{3} x ^{15 - 9}}{8 y ^{12}}

Subtract the numbers:

15 - 9 = 6

= \frac{x ^{6} y ^{3}}{8 y ^{12}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{y ^{3}}{y ^{12}} = \frac{1}{y ^{12 - 3}}

= \frac{x ^{6}}{8 y ^{12 - 3}}

Subtract the numbers:

12 - 3 = 9

= \frac{x ^{6}}{8 y ^{9}}

[3 \frac{x}{4} + 2 \frac{y}{4}]^{3}

(x + 3) (y + 6)

(\frac{( 2 x )}{( 3 y )} + \frac{( 2 y )}{( 3 x )})^{2}

m^{2} \cdot n^{4} + m^{3} \cdot n^{3} - m^{4} \cdot n^{2} - m^{4} \cdot n^{4}

10 - (x + 10)^{3}

What is ((x^5y)/(2x^3y^4))^3 ?
The solution to ((x^5y)/(2x^3y^4))^3 is (x^6)/(8y^9)