What is 1x^a+2y^x0.1+3x^ay^x+1 ?

The solution to 1x^a+2y^x0.1+3x^ay^x+1 is x^a+0.2y^x+3x^ay^x+1

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simplify 1x^a+2y^x0.1+3x^ay^x+1

simplify

1 x^{a} + 2 y^{x} 0.1 + 3 x^{a} y^{x} + 1

x^{a} + 0.2 y^{x} + 3 x^{a} y^{x} + 1

Solution steps

1 \cdot x^{a} + 2 y^{x} \cdot 0.1 + 3 x^{a} y^{x} + 1

1 \cdot x^{a} = x^{a}

2 y^{x} \cdot 0.1 = 0.2 y^{x}

= x^{a} + 0.2 y^{x} + 3 x^{a} y^{x} + 1

(- a^{3} \cdot b^{2})^{5}

2 (3 + 5 x)^{3} + 3

(8 x^{4} \cdot y^{3})^{2}

x^{2} + 3 x - 2 x y - 6 y

121 x^{2} + 81 y^{2} - 198 x y

What is 1x^a+2y^x0.1+3x^ay^x+1 ?
The solution to 1x^a+2y^x0.1+3x^ay^x+1 is x^a+0.2y^x+3x^ay^x+1