What is factor 27m^3+64n^3 ?

The solution to factor 27m^3+64n^3 is (3m+4n)(9m^2-12mn+16n^2)

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factor 27m^3+64n^3

factor

27 m^{3} + 64 n^{3}

(3 m + 4 n) (9 m^{2} - 12 mn + 16 n^{2})

Solution steps

27 m^{3} + 64 n^{3}

Apply exponent rules

= (3 m)^{3} + (4 n)^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(3 m)^{3} + (4 n)^{3} = (3 m + 4 n) ((3 m)^{2} - 3 m \cdot 4 n + (4 n)^{2})

= (3 m + 4 n) ((3 m)^{2} - 3 m \cdot 4 n + (4 n)^{2})

Simplify

(3 m)^{2} - 3 m \cdot 4 n + (4 n)^{2} : 9 m^{2} - 12 mn + 16 n^{2}

= (3 m + 4 n) (9 m^{2} - 12 mn + 16 n^{2})

x^{3} + 2 x^{2} \cdot y - x - 2 y

(x y^{4})^{3}

(\frac{x ^{- 3}}{y ^{4}})^{- 5}

m + t \frac{1}{2} \cdot j \cdot (- \frac{3}{4}) \cdot j \cdot \frac{15}{65}

- 5 - 2 x

What is factor 27m^3+64n^3 ?
The solution to factor 27m^3+64n^3 is (3m+4n)(9m^2-12mn+16n^2)