What are the solutions to the equation y^2+3y+9/4 =0 ?

The solutions to the equation y^2+3y+9/4 =0 are y=-3/2

Find the zeros of y^2+3y+9/4 =0

The zeros of y^2+3y+9/4 =0 are y=-3/2

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y^{2} + 3 y + \frac{9}{4} = 0

y = - \frac{3}{2}

Decimal Notation

y = - 1.5

Solution steps

y^{2} + 3 y + \frac{9}{4} = 0

Multiply both sides by

4

4 y^{2} + 12 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

y_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

y = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

y = - \frac{3}{2}

The solution to the quadratic equation is:

y = - \frac{3}{2}

11 = \frac{1}{2} (7 x - 8)

6 \cdot 2^{3}

57 = x^{2}

- 16 v + (- 4 v) - (- 7 v) + (- 6) = 20

3 (6 x + 5) \leq 4 (4 x + 5)

What are the solutions to the equation y^2+3y+9/4 =0 ?
The solutions to the equation y^2+3y+9/4 =0 are y=-3/2
Find the zeros of y^2+3y+9/4 =0
The zeros of y^2+3y+9/4 =0 are y=-3/2