What is factor 2x^5-4x^4-9x^3+18x^2+4x-8 ?

The solution to factor 2x^5-4x^4-9x^3+18x^2+4x-8 is (x-2)^2(2x^2-1)(x+2)

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factor 2x^5-4x^4-9x^3+18x^2+4x-8

factor

2 x^{5} - 4 x^{4} - 9 x^{3} + 18 x^{2} + 4 x - 8

(x - 2)^{2} (2 x^{2} - 1) (x + 2)

Solution steps

2 x^{5} - 4 x^{4} - 9 x^{3} + 18 x^{2} + 4 x - 8

Use the rational root theorem

= (x - 2) \frac{2 x ^{5} - 4 x ^{4} - 9 x ^{3} + 18 x ^{2} + 4 x - 8}{x - 2}

\frac{2 x ^{5} - 4 x ^{4} - 9 x ^{3} + 18 x ^{2} + 4 x - 8}{x - 2} = 2 x^{4} - 9 x^{2} + 4

= (x - 2) (2 x^{4} - 9 x^{2} + 4)

Factor

2 x^{4} - 9 x^{2} + 4 : (2 x^{2} - 1) (x + 2) (x - 2)

= (x - 2) (2 x^{2} - 1) (x + 2) (x - 2)

Apply exponent rule:

aa = a^{2}

(x - 2) (x - 2) = (x - 2)^{2}

= (x - 2)^{2} (2 x^{2} - 1) (x + 2)

\frac{4 x ^{1}}{9}

16.1 x^{2} x + 50

\frac{16 x ^{2} + 4 x}{4 x}

(x - y)^{6} - 8 x^{3}

\frac{( c + 4 )}{( c - 4 )} - \frac{( c - 3 )}{( c + 4 )}

What is factor 2x^5-4x^4-9x^3+18x^2+4x-8 ?
The solution to factor 2x^5-4x^4-9x^3+18x^2+4x-8 is (x-2)^2(2x^2-1)(x+2)