What is ((x^2+2x))/((x^2+4x+4)) ?

The solution to ((x^2+2x))/((x^2+4x+4)) is x/(x+2)

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simplify ((x^2+2x))/((x^2+4x+4))

simplify

\frac{( x ^{2} + 2 x )}{( x ^{2} + 4 x + 4 )}

\frac{x}{x + 2}

Solution steps

\frac{x ^{2} + 2 x}{x ^{2} + 4 x + 4}

Factor

x^{2} + 2 x : x (x + 2)

= \frac{x ( x + 2 )}{x ^{2} + 4 x + 4}

Factor

x^{2} + 4 x + 4 : (x + 2)^{2}

= \frac{x ( x + 2 )}{( x + 2 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x + 2)^{2} = (x + 2) (x + 2)

= \frac{x ( x + 2 )}{( x + 2 ) ( x + 2 )}

Cancel the common factor:

x + 2

= \frac{x}{x + 2}

(d^{3} - 2 d)^{4}

(4 - d)^{3}

\frac{( - 3 x ^{5} y ^{3} )}{( - 4 x ^{2} y )}

sin^{2} (x) sec^{2} (x)

\frac{5 y ^{2} - 20}{y ^{2} - 9 y + 14}

What is ((x^2+2x))/((x^2+4x+4)) ?
The solution to ((x^2+2x))/((x^2+4x+4)) is x/(x+2)