What is (d)-4.2^n-((-1))/4*n^2-1/5*n+1/8 ?

The solution to (d)-4.2^n-((-1))/4*n^2-1/5*n+1/8 is d-4.2^n+(n^2)/4-n/5+1/8

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simplify (d)-4.2^n-((-1))/4n^2-1/5n+1/8

simplify

(d) - 4. 2^{n} - \frac{( - 1 )}{4} \cdot n^{2} - \frac{1}{5} \cdot n + \frac{1}{8}

d - 4. 2^{n} + \frac{n ^{2}}{4} - \frac{n}{5} + \frac{1}{8}

Solution steps

(d) - 4. 2^{n} - \frac{- 1}{4} n^{2} - \frac{1}{5} n + \frac{1}{8}

Apply rule:

(a) = a

(d) = d

= d - 4. 2^{n} - \frac{- 1}{4} n^{2} - \frac{1}{5} n + \frac{1}{8}

\frac{- 1}{4} n^{2} = - \frac{n ^{2}}{4}

\frac{1}{5} n = \frac{n}{5}

= d - 4. 2^{n} - (- \frac{n ^{2}}{4}) - \frac{n}{5} + \frac{1}{8}

Apply rule:

a - (- b) = a + b

- 4. 2^{n} - (- \frac{n ^{2}}{4}) = - 4. 2^{n} + \frac{n ^{2}}{4}

= d - 4. 2^{n} + \frac{n ^{2}}{4} - \frac{n}{5} + \frac{1}{8}

\frac{- 1}{2 x ^{2}}

(- 5 a)^{3}

x^{2} - (3 + 1) \cdot x + 3

\frac{6 - 1 x ^{0} + 6}{6}

5 x + 8 x + 5 y - 9 y + 10 z - z

What is (d)-4.2^n-((-1))/4*n^2-1/5*n+1/8 ?
The solution to (d)-4.2^n-((-1))/4*n^2-1/5*n+1/8 is d-4.2^n+(n^2)/4-n/5+1/8