What is ((2x^2-3x-9))/((4x^2-9)) ?

The solution to ((2x^2-3x-9))/((4x^2-9)) is (x-3)/(2x-3)

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simplify ((2x^2-3x-9))/((4x^2-9))

simplify

\frac{( 2 x ^{2} - 3 x - 9 )}{( 4 x ^{2} - 9 )}

\frac{x - 3}{2 x - 3}

Solution steps

\frac{2 x ^{2} - 3 x - 9}{4 x ^{2} - 9}

Factor

2 x^{2} - 3 x - 9 : (2 x + 3) (x - 3)

= \frac{( 2 x + 3 ) ( x - 3 )}{4 x ^{2} - 9}

Factor

4 x^{2} - 9 : (2 x + 3) (2 x - 3)

= \frac{( 2 x + 3 ) ( x - 3 )}{( 2 x + 3 ) ( 2 x - 3 )}

Cancel the common factor:

2 x + 3

= \frac{x - 3}{2 x - 3}

\frac{( 3 x + 1 )}{( 3 x ^{2} + 2 x )}

2 x^{2} + 84 x - 864

\frac{6}{a} - \frac{1}{b}

(x - 2 y + 3)^{3}

(w + 7) (2 w - 2 u - 3)

What is ((2x^2-3x-9))/((4x^2-9)) ?
The solution to ((2x^2-3x-9))/((4x^2-9)) is (x-3)/(2x-3)