What are the solutions to the equation y^2+4=0 ?

The solutions to the equation y^2+4=0 are y=2i,y=-2i

Find the zeros of y^2+4=0

The zeros of y^2+4=0 are y=2i,y=-2i

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y^{2} + 4 = 0

y = 2 i, y = - 2 i

Solution steps

y^{2} + 4 = 0

Move

4

to the right side

y^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 4, y = - - 4

- 4 = 2 i

- - 4 = - 2 i

y = 2 i, y = - 2 i

(12 x^{2})^{2}

\frac{3}{4} x^{2} + 1 = 16

(a^{3} + 5 a^{2} - 4) \cdot (2 a^{2} - a - 1)

163.8444 e^{0.3662 (0)} + C = 200

∣ 4 x + 3 ∣ < 14

What are the solutions to the equation y^2+4=0 ?
The solutions to the equation y^2+4=0 are y=2i,y=-2i
Find the zeros of y^2+4=0
The zeros of y^2+4=0 are y=2i,y=-2i