What is 1.6x^2-4(y^2)/2 y+0.4x ?

The solution to 1.6x^2-4(y^2)/2 y+0.4x is 1.6x^2-2y^3+0.4x

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simplify 1.6x^2-4(y^2)/2 y+0.4x

simplify

1.6 x^{2} - 4 \frac{y ^{2}}{2} y + 0.4 x

1.6 x^{2} - 2 y^{3} + 0.4 x

Solution steps

1.6 x^{2} - 4 \cdot \frac{y ^{2}}{2} y + 0.4 x

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

4 \cdot \frac{y ^{2}}{2} y = \frac{4 y ^{2} y}{2}

= 1.6 x^{2} - \frac{4 y ^{2} y}{2} + 0.4 x

Divide the numbers:

\frac{4}{2} = 2

= 1.6 x^{2} - 2 y^{2} y + 0.4 x

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{2} y = y^{2 + 1}

= 1.6 x^{2} - 2 y^{2 + 1} + 0.4 x

Add the numbers:

2 + 1 = 3

= 1.6 x^{2} - 2 y^{3} + 0.4 x

\frac{( 2 ^{n} + 2 ^{n - 1} )}{( 2 ^{n - 1} - 2 ^{n} )}

(\frac{p ^{2} - 3}{2 \cdot q ^{2}})^{3}

(3 x^{4} \cdot y^{- 5})^{3}

(sec (x) - tan (x)) 2

(- 5) (2 a - 3 b + 5 c) - 4 (2 a + 6 - 2 c)

What is 1.6x^2-4(y^2)/2 y+0.4x ?
The solution to 1.6x^2-4(y^2)/2 y+0.4x is 1.6x^2-2y^3+0.4x