What is (2x^{-2}y^3)^3 ?

The solution to (2x^{-2}y^3)^3 is (8y^9)/(x^6)

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simplify (2x^{-2}y^3)^3

simplify

(2 x^{- 2} y^{3})^{3}

\frac{8 y ^{9}}{x ^{6}}

Solution steps

(2 x^{- 2} y^{3})^{3}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(2 x^{- 2} y^{3})^{3} = 2^{3} (x^{- 2})^{3} (y^{3})^{3}

= 2^{3} (x^{- 2})^{3} (y^{3})^{3}

2^{3} = 8

= 8 (x^{- 2})^{3} (y^{3})^{3}

Simplify

(x^{- 2})^{3} : \frac{1}{x ^{6}}

= 8 \cdot \frac{1}{x ^{6}} (y^{3})^{3}

Simplify

(y^{3})^{3} : y^{9}

= 8 \cdot \frac{1}{x ^{6}} y^{9}

Simplify

8 \cdot \frac{1}{x ^{6}} y^{9} : \frac{8 y ^{9}}{x ^{6}}

= \frac{8 y ^{9}}{x ^{6}}

h \cdot (\frac{- 1}{2})^{- 4}

(\frac{x + y}{3})^{2}

(x - 10)^{2} - (x - 15) (x + 15) - 20 x

4 x^{3} - 16 x^{2} + 20 x - 8

\frac{( y ^{\frac{1}{10}} \cdot y ^{- \frac{3}{2}} )}{( y ^{- \frac{1}{5}} )}