What is ((4y^2-16))/((y^2+3y+2)) ?

The solution to ((4y^2-16))/((y^2+3y+2)) is (4(y-2))/(y+1)

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simplify ((4y^2-16))/((y^2+3y+2))

simplify

\frac{( 4 y ^{2} - 16 )}{( y ^{2} + 3 y + 2 )}

\frac{4 ( y - 2 )}{y + 1}

Solution steps

\frac{4 y ^{2} - 16}{y ^{2} + 3 y + 2}

Factor

4 y^{2} - 16 : 4 (y + 2) (y - 2)

= \frac{4 ( y + 2 ) ( y - 2 )}{y ^{2} + 3 y + 2}

Factor

y^{2} + 3 y + 2 : (y + 1) (y + 2)

= \frac{4 ( y + 2 ) ( y - 2 )}{( y + 1 ) ( y + 2 )}

Cancel the common factor:

y + 2

= \frac{4 ( y - 2 )}{y + 1}

- 0.4 (- 6 g - 6 h) - 2 h - 0.2 (- 5 h + 3 g)

(\frac{( 3 x )}{2 + 1})^{2}

\frac{c ^{3}}{c ^{9}}

(2 x^{2} + 1)^{7}

\frac{( 2 x + 6 )}{2}

What is ((4y^2-16))/((y^2+3y+2)) ?
The solution to ((4y^2-16))/((y^2+3y+2)) is (4(y-2))/(y+1)