What is expand 2x(3x^3-5x^2+7x-5) ?

The solution to expand 2x(3x^3-5x^2+7x-5) is 6x^4-10x^3+14x^2-10x

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expand 2x(3x^3-5x^2+7x-5)

expand

2 x (3 x^{3} - 5 x^{2} + 7 x - 5)

6 x^{4} - 10 x^{3} + 14 x^{2} - 10 x

Solution steps

2 x (3 x^{3} - 5 x^{2} + 7 x - 5)

Distribute parentheses

= 2 x \cdot 3 x^{3} + 2 x (- 5 x^{2}) + 2 x \cdot 7 x + 2 x (- 5)

Simplify

2 x \cdot 3 x^{3} + 2 x (- 5 x^{2}) + 2 x \cdot 7 x + 2 x (- 5) : 6 x^{4} - 10 x^{3} + 14 x^{2} - 10 x

= 6 x^{4} - 10 x^{3} + 14 x^{2} - 10 x

(\frac{x + 4}{3 y ^{2}})^{2}

17.8 x 1 0^{3} - 4.5 x 1 0^{3}

x^{2} - 2 x + 1 - y^{2}

\frac{( ( x + y ) ^{3} - 2 y \cdot ( y + x ) ^{2} )}{( x ^{2} + y ^{2} )}

16 x^{3} \cdot y^{2} - 8 x^{4} \cdot y - 24 x^{2} \cdot y - 40 x^{2} \cdot y^{3}

What is expand 2x(3x^3-5x^2+7x-5) ?
The solution to expand 2x(3x^3-5x^2+7x-5) is 6x^4-10x^3+14x^2-10x