What is factor 81a^4-16b^4 ?

The solution to factor 81a^4-16b^4 is (9a^2+4b^2)(3a+2b)(3a-2b)

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factor 81a^4-16b^4

factor

81 a^{4} - 16 b^{4}

(9 a^{2} + 4 b^{2}) (3 a + 2 b) (3 a - 2 b)

Solution steps

81 a^{4} - 16 b^{4}

81 a^{4} = (9 a^{2})^{2}

16 b^{4} = (4 b^{2})^{2}

= (9 a^{2})^{2} - (4 b^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(9 a^{2})^{2} - (4 b^{2})^{2} = (9 a^{2} + 4 b^{2}) (9 a^{2} - 4 b^{2})

= (9 a^{2} + 4 b^{2}) (9 a^{2} - 4 b^{2})

Factor

9 a^{2} - 4 b^{2} : (3 a + 2 b) (3 a - 2 b)

= (9 a^{2} + 4 b^{2}) (3 a + 2 b) (3 a - 2 b)

\frac{6 x ^{6} + 6 - 6}{6}

(8 x + 1)^{3} + 2^{3}

6 x cos^{3} (x) - 5 cos (x)

10 \frac{m}{s} + 2.25 \frac{m}{s ^{2}}

(\frac{1}{4} \cdot a^{2} - \frac{5}{2} \cdot a) + \frac{1}{2} \cdot a

What is factor 81a^4-16b^4 ?
The solution to factor 81a^4-16b^4 is (9a^2+4b^2)(3a+2b)(3a-2b)