What is (a^3b^3)-(a^2+2a^3-b^3) ?

The solution to (a^3b^3)-(a^2+2a^3-b^3) is a^3b^3-a^2-2a^3+b^3

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simplify (a^3b^3)-(a^2+2a^3-b^3)

simplify

(a^{3} b^{3}) - (a^{2} + 2 a^{3} - b^{3})

a^{3} b^{3} - a^{2} - 2 a^{3} + b^{3}

Solution steps

(a^{3} b^{3}) - (a^{2} + 2 a^{3} - b^{3})

Apply rule:

(a) = a

(a^{3} b^{3}) = a^{3} b^{3}

= a^{3} b^{3} - (a^{2} + 2 a^{3} - b^{3})

Apply the distributive law:

- (a + b) = - a - b

- (a^{2} + 2 a^{3} - b^{3}) = - a^{2} - 2 a^{3} + b^{3}

= a^{3} b^{3} - a^{2} - 2 a^{3} + b^{3}

10 + 5 j

16 x^{4} + 9 y^{4} + 24 x^{2} \cdot y^{2}

(2 a + 3) (3 a + 2 b)

x 3 y^{23}

a (- 2.3) b (5.4) c (2 - 6)

What is (a^3b^3)-(a^2+2a^3-b^3) ?
The solution to (a^3b^3)-(a^2+2a^3-b^3) is a^3b^3-a^2-2a^3+b^3