What is (x-3x)^2-a(x^2-3x)-20 ?

The solution to (x-3x)^2-a(x^2-3x)-20 is 4x^2-a(x^2-3x)-20

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simplify (x-3x)^2-a(x^2-3x)-20

simplify

(x - 3 x)^{2} - a (x^{2} - 3 x) - 20

4 x^{2} - a (x^{2} - 3 x) - 20

Solution steps

(x - 3 x)^{2} - a (x^{2} - 3 x) - 20

Add similar elements:

x - 3 x = - 2 x

= (- 2 x)^{2} - a (x^{2} - 3 x) - 20

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2 x)^{2} = (2 x)^{2}

= (2 x)^{2} - a (x^{2} - 3 x) - 20

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(2 x)^{2} = 2^{2} x^{2}

= 2^{2} x^{2} - a (x^{2} - 3 x) - 20

2^{2} = 4

= 4 x^{2} - a (x^{2} - 3 x) - 20

\frac{( ( x ^{6} \cdot y ^{8} ) ^{3} )}{( x ^{2} \cdot y ^{2} )}

\frac{8 x}{2}

- 8 (- 6 n + 5) - 4 (8 + 3 n)

\frac{x ^{2} + x + 1}{( x + 2 ) ^{3} - ( x - 2 ) ^{3}}

7 m^{2} - \frac{11}{3} m - \frac{2}{3}

What is (x-3x)^2-a(x^2-3x)-20 ?
The solution to (x-3x)^2-a(x^2-3x)-20 is 4x^2-a(x^2-3x)-20