What is expand (x^2-4y^2)^3 ?

The solution to expand (x^2-4y^2)^3 is x^6-12x^4y^2+48x^2y^4-64y^6

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expand (x^2-4y^2)^3

expand

(x^{2} - 4 y^{2})^{3}

x^{6} - 12 x^{4} y^{2} + 48 x^{2} y^{4} - 64 y^{6}

Solution steps

(x^{2} - 4 y^{2})^{3}

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(x^{2} - 4 y^{2})^{3} = (x^{2})^{3} - 3 (x^{2})^{2} \cdot 4 y^{2} + 3 x^{2} (4 y^{2})^{2} - (4 y^{2})^{3}

= (x^{2})^{3} - 3 (x^{2})^{2} \cdot 4 y^{2} + 3 x^{2} (4 y^{2})^{2} - (4 y^{2})^{3}

Simplify

(x^{2})^{3} - 3 (x^{2})^{2} \cdot 4 y^{2} + 3 x^{2} (4 y^{2})^{2} - (4 y^{2})^{3} : x^{6} - 12 x^{4} y^{2} + 48 x^{2} y^{4} - 64 y^{6}

= x^{6} - 12 x^{4} y^{2} + 48 x^{2} y^{4} - 64 y^{6}

\frac{( 3 a )}{( 16 - 4 a )} + \frac{3}{( a - 4 )}

2^{3 n}

[\frac{1}{2 \cdot x + y}]^{2}

\frac{1 + tan ^{2} ( a )}{1 + cot ^{2} ( a )}

3 w - 52 w + w - 7

What is expand (x^2-4y^2)^3 ?
The solution to expand (x^2-4y^2)^3 is x^6-12x^4y^2+48x^2y^4-64y^6