What are the solutions to the equation 4x^2+5x+7=0 ?

The solutions to the equation 4x^2+5x+7=0 are x=-5/8+i(sqrt(87))/8 ,x=-5/8-i(sqrt(87))/8

Find the zeros of 4x^2+5x+7=0

The zeros of 4x^2+5x+7=0 are x=-5/8+i(sqrt(87))/8 ,x=-5/8-i(sqrt(87))/8

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4 x^{2} + 5 x + 7 = 0

x = - \frac{5}{8} + i \frac{87}{8}, x = - \frac{5}{8} - i \frac{87}{8}

Solution steps

4 x^{2} + 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

Simplify

5^{2} - 4 \cdot 4 \cdot 7 : 87 i

x_{1, 2} = \frac{- 5 \pm 87 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 87 i}{2 \cdot 4}, x_{2} = \frac{- 5 - 87 i}{2 \cdot 4}

x = \frac{- 5 + 87 i}{2 \cdot 4} : - \frac{5}{8} + i \frac{87}{8}

x = \frac{- 5 - 87 i}{2 \cdot 4} : - \frac{5}{8} - i \frac{87}{8}

The solutions to the quadratic equation are:

x = - \frac{5}{8} + i \frac{87}{8}, x = - \frac{5}{8} - i \frac{87}{8}

2 x < 5 - 3 x

x k - x y - x^{2} + y k

(3 + 6) (23 - 56)

f = 2 (- 2)^{2} - 3 (- 2)

4

What are the solutions to the equation 4x^2+5x+7=0 ?
The solutions to the equation 4x^2+5x+7=0 are x=-5/8+i(sqrt(87))/8 ,x=-5/8-i(sqrt(87))/8
Find the zeros of 4x^2+5x+7=0
The zeros of 4x^2+5x+7=0 are x=-5/8+i(sqrt(87))/8 ,x=-5/8-i(sqrt(87))/8